Friday, November 11, 2011

Calculating Earth's magnetic field in Teslas?

How do you measure Earth's main field near the core, would it be around 100,000 Gauss or 10 Teslas? What equations do I use? Background info: The internal field of the Earth (its "main field") appears to be generated in the Earth's core by a dynamo process, associated with the circulation of liquid metal in the core, driven by internal heat sources. Its major part resembles the field of a bar magnet ("dipole field") inclined by about 10掳 to the rotation axis of Earth, but more complex parts ("higher harmonics") also exist, as first shown by Carl Friedrich Gauss. The dipole field has an intensity of about 30,000-60,000 nanoteslas (nT) at the Earth's surface, and its intensity diminishes like the inverse of the cube of the distance, i.e. at a distance of R Earth radii it only amounts to 1/R鲁 of the surface field in the same direction. Higher harmonics diminish faster, like higher powers of 1/R, making the dipole field the only important internal source in most of the magnetosphe|||I am writing a sci fi using naturally occuring magnetism as a big ingredient.


From things I've seen, Rock planets (Murcury, Venus, Earth %26amp; Mars) would have different calculations than the Gas planets (Jupiter, Saturn, Uranus, Neptune).


So mass and rotation speed are also big factors in calculating a planetary magnetic field.





Did you also know that earthquakes and eruptions have magnetic fields ...

No comments:

Post a Comment